AW: [cvsnt] date command in the loginfo file
Christian Manhart
christian.manhart at ifs-it.de
Wed Apr 16 15:52:16 BST 2003
You have to separate the individual shell commands with an ampersand.
But be carefull as this creates several lines of output (this is the
reason why I add an extra separation line) !
I'm not sure if Win32 shell is able to produce all the output on one
line without using external tools - at least I could not manage to do
so :-(
I'm using the following entry in loginfo
DEFAULT (echo ---------------------------------------- & \
echo ${USER} & \
echo %{sVv} & \
date /t & \
time /t) >> $CVSROOT/CVSROOT/commitlog
resulting in a multiline entry like:
----------------------------------------
<user>
"<dir1>/<dir2> <file>,1.3,1.4"
Mo 14.04.2003
14:34
HTH,
Christian Manhart
------------------------------------------------------------------------
> IFS Informationstechnik GmbH -- http://www.ifs-it.de <
------------------------------------------------------------------------
Christian Manhart - Trausnitzstrasse 8, 81671 Muenchen - Germany
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Von: cvsnt-bounces at cvsnt.org [mailto:cvsnt-bounces at cvsnt.org] Im Auftrag
von Norman Clerman
Gesendet: Mittwoch, 16. April 2003 16:31
An: cvsnt
Betreff: [cvsnt] date command in the loginfo file
Good day to all,
I'm running cvsnt (version 1.11.1.3-77a) on a Windows 2000 server.
The one active line in my loginfo file is
DEFAULT (echo ""; id; echo %{sVv}; date; cat) >>
$CVSROOT/CVSROOT/commitlog
Here's a line from my commitlog file:
""; id; echo "design/source zoomtypeM.f90,1.1.1.1,1.2"; date; cat
How do I get the date to print?
Many thanks,
Norm Clerman
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